# Thread: Word problems for fun!

1. Originally Posted by matmos
He should offer one coin each to 1 & 3 and offer nothing to the others.
Incorrect.

2. Okay, I would light the first rope on both ends, that means it would burn down in 30 minutes. Then I cut the second rope in two and do the same thing or light it in the middle, that's another 15 minutes, giving me a total of 45 minutes.

3. Originally Posted by Jonnyboy
Incorrect.
http://mindyourdecisions.com/blog/20...theory-puzzle/

In a Pirate’s Game of N players–and gold pieces outnumber players–if the players are labeled 1, 2 … N, in order of of first to last proposer, player 1 should make a nominal offer to the odd-numbered players 3, 5, 7, etc., and keep the remaining wealth for himself.
Quite possibly.

4. Originally Posted by Red Herring
Okay, I would light the first rope on both ends, that means it would burn down in 30 minutes. Then I cut the second rope in two and do the same thing or light it in the middle, that's another 15 minutes, giving me a total of 45 minutes.
Incorrect

Recall that the ropes are of varying densities. Therefore, the exact length of rope required to burn for 15 minutes cannot be known (e.g. you would be unable to determine where to cut or light the second rope such that you know it will burn for 15 minutes).

5. Originally Posted by matmos
This is not an answer, this is a link to a site. Your previous answer was incorrect, and of this I am certain. Try again.

6. Right. But the 30 minute thing should still work despite the irregular density. Can I split a rope longfside from end to end?

7. Originally Posted by Jonnyboy
This is not an answer, this is a link to a site. Your previous answer was incorrect, and of this I am certain. Try again.
Actually it's a fairly easy puzzle to solve.

The link shows the logic of the puzzle. Granted, it does not serve you the answer on a plate - but I assumed for a brief moment that you are capable of making simple substitutions.

I apologise, Johhnyboy. I got that wrong.

8. Originally Posted by Red Herring
Right. But the 30 minute thing should still work despite the irregular density.
Correct.

Originally Posted by Red Herring
Can I split a rope half length?
You can, but whether or not you end up with one piece which burns for 40.0001 minutes and another that burns for 19.9999 minutes, or some other of the infinitely many combination you do not know. In this case, the ratio of length of time to burn and rope length is not constant.

9. Originally Posted by matmos
Actually it's a fairly easy puzzle to solve.

The link shows the logic of the puzzle. Granted, it does not serve you the answer on a plate - but I assumed for a brief moment that you are capable of making simple substitutions.

I apologise, Johhnyboy. I got that wrong.
You do not need to apologize, and have yet to solve the problem. The solution you gave above is incorrect, and from my brief glance at the website, it isn't applicable to this problem.

Edit:
Truth be told, I find your initial incorrect answer and your citing of this website to be distasteful, when taken together. I cannot help but assume you care more about being perceived as intelligent and right than having fun thinking about the problems.

10. Originally Posted by Jonnyboy
A man has a lighter and two lengths of robe with varying densities. The only thing the man knows about each length of rope is that if he lights an end of a rope, it will burn for exactly one hour; however, it may be that 90% of a rope burns up in 1 minute, and it takes 59 minutes for the remaining section of rope to burn (this is a product of the varying densities).

How can this man accurately measure 45 minutes?
Use a stop watch! Aha...

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