Posts Per Day: 0.69
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Thread: Posts Per Day Mathematics

06222010, 02:13 AM #11
 Join Date
 Dec 2008
 MBTI
 ISTP
 Posts
 473

06222010, 04:58 AM #12
Wolfy! Your Pness is in question.
I'm at 12.01ish atm, fun stuffs. Used to be much higher though.~Selfdepricating Megalomaniacal Superwolf

06222010, 06:11 AM #13
post per day = total posts / days of membership
a = b^x with 10.00 = 10.06^x
x = log(b)a approximately = 0.99741
10.00 = ( 10.06 )^0.99741
10.00 = 10.06 * ( x/y )^0.99741
with x >= 1 and y >= 1 and x = new posts per day and y = new days since today
> [10.00 / 10.06]^0.99741 = x/y
> x/y approximately = 0,9941
means 9,941 posts in the next 10,000 days or 9.941 posts in the next ten days
> 10.06 * 9.941 / 10 = approximately 10.00
of course you may vary x/y = 0,9941 by posts / day as you like:
For example:
9.941 posts / 10 days
> 9.941 * x = 10 > x = 1,005935
so: 1,005935 * ( 9.941 / 10 ) = 10 / 10,05935
so 10 posts in the next 10 days 1 hour 25 minutes 27 seconds 840 milliseconds

06222010, 06:22 AM #14
Milliseconds.... that's a nice touch.
"Hey Capa  We're only stardust." ~ "Sunshine"
“Pleasure to me is wonder—the unexplored, the unexpected, the thing that is hidden and the changeless thing that lurks behind superficial mutability. To trace the remote in the immediate; the eternal in the ephemeral; the past in the present; the infinite in the finite; these are to me the springs of delight and beauty.” ~ H.P. Lovecraft

06222010, 06:47 AM #15

06222010, 07:01 AM #16
Dude, what?
Taken from Wolfy's statistics page:
Total Posts: 7,270
Posts Per Day: 10.07 (Which is unusable due to it being rounded to two decimals)
Join Date: 06302008
06302008 > 06222010 = 722 days
Doesn't take a genius to figure out what post difference he has between his current posts per day and the exact 10.00 posts per day. You should be able to see it instantly, but for funs I'll actualy post how to reach it. :P
7270(722*10)=50 posts above the 10.00 mark.
Who needs a calculator for that.
So if he posts less than ten posts per day and accumelates the posts he is short of ten a day, until he accumelates 50 posts, he will be back at 10.00 with exact precision. Or just don't post for 5 days.
You say 10 posts in the next 10 days he will be at 10.00? Whilest in fact he will be 40 posts shy of exact 10.00 if he does that.
My method is both easier to calculate and much more exact. Hmpf! One mistake in your method is assuming his 10.06 was a precise factor, whilest in fact it is a rounded number, and currently is 10,069252077562326869806094182825 (Was probably closer to 10.06 at the time of your post though.)
edit: Ofcourse, I didn't take into account the post difference of Wolfy since your post, but you still should have calculated the exact coeffecient first. :P~Selfdepricating Megalomaniacal Superwolf

06222010, 07:08 AM #17
Ya I figured it doesnt work, but well first I wanted to do a laplace transformation

06222010, 07:11 AM #18

06222010, 07:54 AM #19
obvious solutions are boring
Mistake is here: 10.00 = total post + x / days of membership + y
Tho were to go from here ?
I brought it to: 10.00 = tp ( 1 + x/tp ) / dom ( 1 + y/dom)
But I am running out of ideas from there.
think there is no workaround but to laplace transform it, like:
tpd + x = dom + y
with g(0) = 10.00
and f(t) = tpd + x(t) / dom + y(t)
> g(0) = (1st derivation) f(t)
> Transformation into imaginal area:
0 = 1  s * g(t)
> U(s) = 1 / s
something, I dunno. Have to look into my controltechniques exam .

06222010, 08:23 AM #20
with laplace I end up with:
G(s) = 10 / [(tp + x) / dom + y]
So if he has 7,270 posts in 722 days its:
> 7220 + 10 y / 7,270 + x = 1
So if he doesnt post for 50 days you get y = 50 and x = 0
That works
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