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  1. #11
    pathwise dependent FDG's Avatar
    Join Date
    Aug 2007


    Quote Originally Posted by ubiquitous1 View Post
    I think I understand what you are saying, but triple integrals are still used to find a volume.

    V=∫∫∫ dz dy dx

    Where the limits of integration for z are 0 to 1-y, limits for y are 0 to 1 and finally limits of x are 0 to 2.

    I miss Calculus
    That's how we used to do it, too, although it's conceptually rather primitive.
    ENTj 7-3-8 sx/sp

  2. #12


    How you approach it depends on what you are solving. For A(h)=pi*h^2 (ie. a form of cone), you wouldn't need to perform a triple integral to find the volume. If you work it from basics it is a triple integral though, because the area came from integration over r and theta, then setting r=h.

    So triple integrals are used to find volume from scratch, but are not always a necessary step if you recognise how the cross-sectional area behaves. That was the formula onemoretime had, which may or may not be useful depending on what needs to be solved.
    Freude, schöner Götterfunken Tochter aus Elysium, Wir betreten feuertrunken, Himmlische, dein Heiligtum! Deine Zauber binden wieder Was die Mode streng geteilt; Alle Menschen werden Brüder, Wo dein sanfter Flügel weilt.

  3. #13
    The Eighth Colour Octarine's Avatar
    Join Date
    Oct 2007
    10w so

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