When we divide the agent do we divide the object?
Let's have a catch of 22.
Say 9 X 3 = 27
> 9 X 8 = T(27)
on account of (22/2)  8 = 3
9 X 4 = 36
11  4 = 7
9 X 7 = T(9 X 4)
9 X 5 = T(9 X 6)
9 X 2 = T(9 X 9)
22 = T(22)
22/2 = 11 = T(11)
we need 100  1
Back to 9 X 3
= 27
> 99 X 3 = 297
on account of 11  3 = 8
hence 99 X 8 = T(99 X 3)
>9 X 4 = 36
99 X 4 = 396
11  4 = 7
>99 X 7 =T(99 X 4)
9 X 5 = 45
>99 X 5 = 495
11  5 = 6
99 X 6 = T(99 X 5)
2 + 9 = 11
>99 X 2 = T(99 X 9).
 22 + (22/2) =  11 etc .. :
 22
 11
x00
+11
+22
+33
+44
+55
+66
+77
+88
+99
110
121
14/2 = 7
99 X 7 = 693
T(693) = 396
we need an Uturn.
User Tag List
Thread: Catch22

06122010, 03:38 AM #1
Catch22

06122010, 04:36 AM #2
 1 + 100
(100  1) + 22 = 121
Differentiate X = T(X)
121 = (21 + 19 + 17 + 15 + 13 + 11 + 09 + 07 + 05 + 03 + 01 + 0)
the Uturn:
121  0
100 1
81  4
64  9
49  16
36  25
99 X 7 = T(451  55)
check
100 = (19 + 17 + 15 + 13 + 11 + 9 + 7 + 5 + 3 + 1)
100  1
081  4
064  9
036  25
330  55 = 275 = 55 X 5:
99
77
55
33
11
(T1 X 55) + 22
= T(275)

06122010, 10:03 PM #3
so this goes back to the question of "is the whole a thing unto itself or a composite of it's parts?"
“Oh, we're always alright. You remember that. We happen to other people.” Terry Pratchett

06132010, 09:31 AM #4
Exactly. One is all we ever had. It is all there.

06132010, 09:21 PM #5
The question of whatever reminds me of our earlier discussion of the interelationship of 100 and 36. In view of the dichotomy above, another lesson in basicness.
100 = T(5) X 2 =
(19 + 17) + (15 + 13 + 11 + 9 + 7 + 5 + 3) + 1
=
+19
+17
+15
+13
+11
+09
+07
+05
+03
+01
= the dichotomy of T(2) X 5
The d. of 36 = 19 + 17
The d. of T(36) = 15 + 13 + 11 + 9 + 7 + 5 + 3
T(1) = 10
100  36 = T(36) + 1

06272010, 12:55 AM #6
Apropos we define the axiom:
100 = the number in loci.
When we illustrated the function order, the axioms were there but we did not define them.
What was the number of the loci we needed to illustrate the function order?
As I recall 16 X 4 = 64 = 2(32) = 8 X 8
32 was the number of loci for function order. We doubled the number for the reason to illustrate the interchange. The key number was 9.
9 X 4 = 36
8 X 4 = 36  4 = 32
Number in loci for the interplay of axioms =
100 = 64 + 32 + 4
Number of loci = 36  22/2 = 100/4 = 24 + 1
100
25
4
1
Function is an eightgame. Four in the middle.
4 + 4 = 8
4  4 = 0
We have differentiated the number in loci and the number of loci.
36  22/2 = 5 X 5 = (8 + 8) + 8 + 1
Definition:
The number of loci for the axioms is eight: ESTJINFP
The number of loci for the complementary axioms corresponds the number of the functions.
That is eight axioms require eight complementary axioms and again eight loci for the interplay of the axioms and one for equilibrium.

06272010, 01:48 AM #7
The functions are complementary units. In other words, interplay is interchange.
Therefore the functions take the place of the complementary axioms in the loci.
The Axioms
E
I
P
J
NSTF
Axiom (A)
Complementary Axiom (C)
Eqilibrium (E)
ACACA
C000C
A0E0A
C000C
ACACA
Number of loci: 25
Number in loci: 100
1 X 25 = 25
4 X 25 = 100
4  0 = 5  1 = 6  2 = 7  3 = 8  4
0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 64
64/4 = 16
2 + 3 + 4 + 5 + 6 + 5 + 4 + 3 = 64/2
32/4 = 8
+ E
= 1 X 1
1 X 4
respectively.

06272010, 02:10 AM #8
Wildcat, no offense but you need to start expressing yourself in complete sentences. I can never understand shit of what's going on in your posts.
[SIGPIC][/SIGPIC]
Teacher (Idyllic), ESEIEI (SiESFj), SLueI, SanguineMelancholy
Sage, True Neutral (Chaotic Good), Type III AntiHero
Inventive > Artistic > Leisurely > Dramatic
7w6 > 4w3 > 9w8, weakside sp/so
Dark Worker (Sacrificing)
Freewheeling Designer
Hayekian Asshole

06272010, 03:25 AM #9
Complete sentences? What it is?
I played truant every time we had grammar at school.
I try free association.
One hundred is the figurelein here.
44444
44444
44444
44444
44444
How many fours do you see?
Five and twenty.
Fiveandtwenty times four makes a hundred.
Think fourwise.
36/4 = 9
36  4 = 32
32/4 = 8
Axiom
8  2 = 6
8  6 = 2
8  8 = 0
8  0 = 8
Complementary Axiom
8  7 = 1
8  1 = 7
8  5 = 3
8  3 = 5
ATTENTION
(8  0):2
= 4
ATTENTION
ACACA
C000C
A0E0A
C000C
ACACA

06272010, 03:40 AM #10GinkgoGuest
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