# Thread: Keirsey on the Rocks

1. ## Keirsey on the Rocks

Keirsey says the prevalence of N is ten per cent.
The MBTI crowd says it is twenty five per cent.
The MBTI crowd is wrong?

Okay.
You take the MBTI test.
It says you are say, 55 per cent N and 45 per cent S.
Are you an N?

55 - 45 = 10

100 - 10 = 90

You are 10 per cent N and 90 per cent X.

The X has got a Janus face.
The 45 bit comes in a double suit.
As much as there is S, there is blank space.

An interesting question.
What is the minimum per centage of N you have to obtain in the test, to actually be an N?

75 per cent provides an exact equilibrium of X and N.
1 + 1 = 2

You take the test and you get
76 per cent N and 24 per cent S.

N - S = 52
100 - 52 = 48

Actual N 52
X 48

As much as there is S, there is blank space.
Now you are an N.

2. 55 - 45 = 10

45 - 55 = -10

3. Originally Posted by lemons
55 - 45 = 10

45 - 55 = -10
Are you all right?

4. Originally Posted by wildcat
Are you all right?
If one is 10 points intuiting, one must also be -10 points sensing. Meaning they don't use sensing.

Is below 0 just an interval or a ratio? There lies a difference of 20 when clearly 55 and 45 has a difference of 10. There is no interval or ratio, but a difference, for there is no 0 sensing.

10 or -10 is no value. 45 and 55 are relative values where one value can not reach below 0.

5. Originally Posted by lemons
If one is 10 points intuiting, one must also be -10 points sensing. Meaning they don't use sensing.

Is below 0 just an interval or a ratio? There lies a difference of 20 when clearly 55 and 45 has a difference of 10. There is no interval or ratio, but a difference, for there is no 0 sensing.

10 or -10 is no value. 45 and 55 are relative values where one value can not reach below 0.
Right. I see you now.
Did not get it at first, dear boy.

My hat is based on per centage. No points.
You are quite right in principle. No objection.

6. P = 100
Zero S = 100 N
and vice versa.

In other words, I cut the bread in the middle.

S 50 = N 50.
S 51 = N 49

Per centage.
Of P.

If you accept S 50 = N 50 you are bound to introduce X.
What is the boundary of X?

#### Posting Permissions

• You may not post new threads
• You may not post replies
• You may not post attachments
• You may not edit your posts
Single Sign On provided by vBSSO