Number Sequences

[Toe-to-toe]

Can you solve these problems?

 

[Fluffywolf]

Solutions I got so far:

Sequence 1:

1) = 78, 97, 81, 48, 304, 503, 307, 013, 8210, 1128

The sequence is as follows

a, a+1=b(inverse), b+2=c, c+3=d(inverse)

78 -> 79 -> 81 -> 84 = 78, 97, 81, 48
304-> 305 -> 307 -> 310 = 304, 503, 307, 013
8210->8211(->8213->8216) = 8210, 1128 (,8213, 6128)

Sequence 2:

1, A, 64, 3E8

decimal - 0123456789
hexadecimal = 0123456789ABCDEF

1= 1
A= 10
64= 6 x16 + 4=100
3E8= (3x16 + 14)x16 + 8=1000

1, A, 64, 3E8 = 1, 10, 100, 1000

sequence 3 (debatable solution):

1, 1, .625, 4/7, 1/3

7/7 = 1
6/6 = 1
5/8 = .625
4/7
3/9 = 1/3

76543=-1 repeated and 76879 = 7-1 = 6+2 = 8-1 = 7+2 = 9 = (-1 -> +2) repeated

 

[Fluffywolf]

Can I ask how strict the third is in terms of reaching an answer? I can imagine there is probably an actually mathematical formula with a repeater that can explain that sequence, but since ms calculator sucks and I dont take the time to write stuff down on paper, I can't be bothered trying to find that formula.

I do see a pattern in it though, which would result in the answer being 4/7. But it's not too obvious.


7/7 = 1
6/6 = 1
5/8 = .625
4/7
3/9 = 1/3

76543=-1 repeated and 76879 = 7-1 = 6+2 = 8-1 = 7+2 = 8 = (-1 -> +2) repeated


The other four sequences seem rather random to me. Probably need some kind of context for them to make sense, just like the second one that is just simple hexadecimal code sequence of 1, 10, 100, 1000. But without knowing about hexadecimal code you won't get it.

The first one with the 013 for example, definately means it's not just a mathematical formula. Otherwise it would just say 13. But what is the context of the sequence amd the meaning of the zero before the thirteen? That must be the riddle. I'll ponder on it some, maybe I'll get it. Hah, I got it!

 

[Toe-to-toe]

Sorry...why the second answer is 64 ?
The third answer must be truth.

2 = 64

Easy one!

I'm still working on the other ones.

 

[Fluffywolf]

Sorry...why the second answer is 64 ?

decimal - 0123456789
hexadecimal = 0123456789ABCDEF

1= 1
A= 10
64= 6 x16 + 4=100
3E8= (3x16 + 14)x16 + 8=1000

1, A, 64, 3E8 = 1, 10, 100, 1000

 

[Toe-to-toe]

I've got it!!!
You're genius

decimal - 0123456789
hexadecimal = 0123456789ABCDEF

1= 1
A= 10
64= 6 x16 + 4=100
3E8= (3x16 + 14)x16 + 8=1000

1, A, 64, 3E8 = 1, 10, 100, 1000

 

[Fluffywolf]

Like that was ever in doubt.


In all fairness though, I've worked with hexadecimal code a lot, so I spotted it rather quickly. Instantly. >.>

edit:

I've not gotten very far with the other four though. Although I can't say I've really tried either. From first observations, none of them seem to have a logical mathematical equasion assigned to them, or perhaps do but are then encoded in one way or another. There are just so many ways of encoding something that it could take a long while to figure these all out.

Now if figuring these out would cure cancer, I'd be all for that. But just so I can say I cracked it is not going to be good enough for me to spend large amounts of time on these.

I'll look at them now and then when I have some time and am on the forum. But I don't think I will be the one to crack the other four. xP

 

[Fluffywolf]

Answer for the first:

78, ?, 81, 48, 304, 503, 307, 013, ?, 1128

Click spoiler

1) = 78, 97, 81, 48, 304, 503, 307, 013, 8210, 1128

The sequence is as follows

a, a+1=b(inverse), b+2=c, c+3=d(inverse)

78 -> 79 -> 81 -> 84 = 78, 97, 81, 48
304-> 305 -> 307 -> 310 = 304, 503, 307, 013
8210->8211(->8213->8216) = 8210, 1128 (,8213, 6128)

 

[herbpixie]

Answer for the first:

78, ?, 81, 48, 304, 503, 307, 013, ?, 1128

Click spoiler

1) = 78, 97, 81, 48, 304, 503, 307, 013, 8210, 1128

The sequence is as follows

a, a+1=b(inverse), b+2=c, c+3=d(inverse)

78 -> 79 -> 81 -> 84 = 78, 97, 81, 48
304-> 305 -> 307 -> 310 = 304, 503, 307, 013
8210->8211(->8213->8216) = 8210, 1128 (,8213, 6128)

 

[Fluffywolf]

I have absolutely no idea where to start with the others though.

The first two numbers of the fourth sequence have an obvious pattern in them (12345 -> 21354), but there are not enough numbers in the sequence to justify the three after that by the same patterns. I doubt they meant for the ? to be 82605 as the fifth number serves no puropose then. But then again, 12345 cant be a coincidence? Anyway, I'm not seeing the logic of the entire sequence. >.<

 

[herbpixie]

I have absolutely no idea where to start with the others though.

The first two numbers of the fourth sequence have an obvious pattern in them (12345 -> 21354), but there are not enough numbers in the sequence to justify the three after that by the same patterns. I doubt they meant for the ? to be 82605 as the fifth number serves no puropose then. But then again, 12345 cant be a coincidence? Anyway, I'm not seeing the logic of the entire sequence. >.<

I saw the same thing in the fourth sequence, but I can't work it out, either.

 

[Fluffywolf]

I saw the same thing in the fourth sequence, but I can't work it out, either.

Yeah, under the assumption that all given numbers are of significance, the fifth number's sudden jump to in the millions seems inexplicable, if you would try to assign any mathematical formula to it.

So it must have a more elusive reason for its numbers, quite possibly to do with the triple 1's, the 83 and 84 as well as the obvious 12345 in the first number and the fact the second also consists out of the numbers 12345.

 

[Fluffywolf]

Just curious, but is anyone else also trying to solve these? Or am I the only one bothered enough to give it some thought? xP

 

[Toe-to-toe]

Answer for the first:

78, ?, 81, 48, 304, 503, 307, 013, ?, 1128

Click spoiler

1) = 78, 97, 81, 48, 304, 503, 307, 013, 8210, 1128

The sequence is as follows

a, a+1=b(inverse), b+2=c, c+3=d(inverse)

78 -> 79 -> 81 -> 84 = 78, 97, 81, 48
304-> 305 -> 307 -> 310 = 304, 503, 307, 013
8210->8211(->8213->8216) = 8210, 1128 (,8213, 6128)

 

[Toe-to-toe]

Just curious, but is anyone else also trying to solve these? Or am I the only one bothered enough to give it some thought? xP

Maybe, these problems are too difficult for others to solve them.

 

[entropie]

Maybe, these problems are too difficult for others to solve them.

for sure

 

[ilikeitlikethat]

69

 

[Fluffywolf]

Maybe, these problems are too difficult for others to solve them.

for sure

 

[Fluffywolf]

Answer for the first:

78, ?, 81, 48, 304, 503, 307, 013, ?, 1128

Click spoiler

1) = 78, 97, 81, 48, 304, 503, 307, 013, 8210, 1128

The sequence is as follows

a, a+1=b(inverse), b+2=c, c+3=d(inverse)

78 -> 79 -> 81 -> 84 = 78, 97, 81, 48
304-> 305 -> 307 -> 310 = 304, 503, 307, 013
8210->8211(->8213->8216) = 8210, 1128 (,8213, 6128)

I got nostalgic and just checked out these number sequences. Although the other three are still lost on me, I somehow failed to see that the one above is also the sum off the previous four encoded numbers which means that there's another inverse I missed.

Like so:

78 -> 79 -> 81 -> 84 = 78, 97(inv), 81, 48(inv)
78+97+81+48=304
304-> 305 -> 307 -> 310 = 304, 503(inv), 307, 013(inv)
304+503+307+013=1127(inv) <- that's the one I missed that explains the two jumps and makes the sequence limitless. (although there is no four numbers prior to the sequence that sums up to 87, so 78 is truly the start of the sequence.)
1127->1128(->1130->1133) = 7211(inv), 1128 (,0311(inv), 1133)

so although my previous answer seemed correct, it actually wasn't and the praise was unfortunately misplaced.

78, 97, 81, 48, 304, 503, 307, 013, 7211, 1128, (0311, 1133)

Weird that I didn't see this when I was working on this before. But I saw it fairly quickly just now.

 

[Cellmold]

Maybe, these problems are too difficult for others to solve them.

Yeah this thread is making me less intelligent by the second. Mathematical intelligence is so much more impressive than any other.

No amount of extra help could ever save me though!