# Thread: Props to whomever solves my puzzles first

1. Originally Posted by rhinosaur
I can show work if you desire.
Originally Posted by ygolo
Rhinosaur extrapolated a little too much, and didn't give the explanation (while Costrin posted just 5 minutes later, and explanation does take a little while to type out).
Meh.

L bot: n1 = 0 1 2 3 4 5
R bot: n2 = 0 1 2 3 4 5 6
11-(n1+n2)={n1+n2+1 or n1+n2-1}
n1+n2=5 or 6

step 1: L sees {0123456}, 6 produces "yes" so n2 != 6
step 2: R sees {012345}, 0 produces "yes" so n1 != 0
step 3: L sees {012345} ... n2 != 5
setp 4: R sees {12345} ... n1 != 1
step 5: L sees {01234} ... n2 != 4
setp 6: R sees {2345}, only 2 produces "yes" so n1 = 2
Since n2 != 4, n2 must be 3

2. Will I be kicked out of the NT club if I say I hate math?

3. Originally Posted by rhinosaur
Meh.

L bot: n1 = 0 1 2 3 4 5
R bot: n2 = 0 1 2 3 4 5 6
11-(n1+n2)={n1+n2+1 or n1+n2-1}
n1+n2=5 or 6

step 1: L sees {0123456}, 6 produces "yes" so n2 != 6
step 2: R sees {012345}, 0 produces "yes" so n1 != 0
step 3: L sees {012345} ... n2 != 5
setp 4: R sees {12345} ... n1 != 1
step 5: L sees {01234} ... n2 != 4
setp 6: R sees {2345}, only 2 produces "yes" so n1 = 2
Since n2 != 4, n2 must be 3
Not quite. For step one: Check if 0 produces a "yes." Remember n1<=5.

Highlight above by pressing CTRL-A (select all) for the hint. Or you could just select the colored text.

4. Reread it hopefully. So we know how much is left? Remainder = x.
N^2 - 2N +1 = X ??
N^2 - 2N + (1-X) = 0

N = 1 + X^(1/2) or N = 1 - X^(1/2) ??

Heh, I came online today to get away from calculus hmk (I don't do so well in that class, go figure. )

5. Originally Posted by Colors
Reread it hopefully. So we know how much is left?

[...]

Heh, I came online today to get away from calculus hmk (I don't do so well in that class, go figure. )
See, that wasn't particularly hard was it?

But for a full explanation you need a bit more:

For instance, because the square vial's width is a positive value (no such thing as a vial with zero or negative width), we know the magic number is positive.

So what if N = 1 - X^(1/2)<=0?

Also, as a general note to people, based on comments I've recieved on the puzzles. It is very imortant to make assumptions/interpretations and to keep track of those assumtions, and then go back and check those assumptions to see if they still make sense. One of the best Engineering professors at Cal. Tech. used to advise his students to "leave behind a wake of assumptions" when solving a problem.

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