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  1. #11
    Just a statistic rhinosaur's Avatar
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    Quote Originally Posted by rhinosaur View Post
    I can show work if you desire.
    Quote Originally Posted by ygolo View Post
    Rhinosaur extrapolated a little too much, and didn't give the explanation (while Costrin posted just 5 minutes later, and explanation does take a little while to type out).
    Meh.

    L bot: n1 = 0 1 2 3 4 5
    R bot: n2 = 0 1 2 3 4 5 6
    11-(n1+n2)={n1+n2+1 or n1+n2-1}
    n1+n2=5 or 6

    step 1: L sees {0123456}, 6 produces "yes" so n2 != 6
    step 2: R sees {012345}, 0 produces "yes" so n1 != 0
    step 3: L sees {012345} ... n2 != 5
    setp 4: R sees {12345} ... n1 != 1
    step 5: L sees {01234} ... n2 != 4
    setp 6: R sees {2345}, only 2 produces "yes" so n1 = 2
    Since n2 != 4, n2 must be 3

  2. #12
    Senior Member Misty_Mountain_Rose's Avatar
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    Will I be kicked out of the NT club if I say I hate math?
    Embrace the possibilities.

  3. #13

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    Quote Originally Posted by rhinosaur View Post
    Meh.

    L bot: n1 = 0 1 2 3 4 5
    R bot: n2 = 0 1 2 3 4 5 6
    11-(n1+n2)={n1+n2+1 or n1+n2-1}
    n1+n2=5 or 6

    step 1: L sees {0123456}, 6 produces "yes" so n2 != 6
    step 2: R sees {012345}, 0 produces "yes" so n1 != 0
    step 3: L sees {012345} ... n2 != 5
    setp 4: R sees {12345} ... n1 != 1
    step 5: L sees {01234} ... n2 != 4
    setp 6: R sees {2345}, only 2 produces "yes" so n1 = 2
    Since n2 != 4, n2 must be 3
    Not quite. For step one: Check if 0 produces a "yes." Remember n1<=5.

    Highlight above by pressing CTRL-A (select all) for the hint. Or you could just select the colored text.

    Accept the past. Live for the present. Look forward to the future.
    Robot Fusion
    "As our island of knowledge grows, so does the shore of our ignorance." John Wheeler
    "[A] scientist looking at nonscientific problems is just as dumb as the next guy." Richard Feynman
    "[P]etabytes of [] data is not the same thing as understanding emergent mechanisms and structures." Jim Crutchfield

  4. #14
    The Destroyer Colors's Avatar
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    Reread it hopefully. So we know how much is left? Remainder = x.
    N^2 - 2N +1 = X ??
    N^2 - 2N + (1-X) = 0

    Quadratic formula shenanigans
    N = 1 + X^(1/2) or N = 1 - X^(1/2) ??


    Heh, I came online today to get away from calculus hmk (I don't do so well in that class, go figure. )

  5. #15

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    Quote Originally Posted by Colors View Post
    Reread it hopefully. So we know how much is left?

    [...]

    Heh, I came online today to get away from calculus hmk (I don't do so well in that class, go figure. )
    See, that wasn't particularly hard was it?

    But for a full explanation you need a bit more:

    For instance, because the square vial's width is a positive value (no such thing as a vial with zero or negative width), we know the magic number is positive.

    So what if N = 1 - X^(1/2)<=0?



    Also, as a general note to people, based on comments I've recieved on the puzzles. It is very imortant to make assumptions/interpretations and to keep track of those assumtions, and then go back and check those assumptions to see if they still make sense. One of the best Engineering professors at Cal. Tech. used to advise his students to "leave behind a wake of assumptions" when solving a problem.

    Accept the past. Live for the present. Look forward to the future.
    Robot Fusion
    "As our island of knowledge grows, so does the shore of our ignorance." John Wheeler
    "[A] scientist looking at nonscientific problems is just as dumb as the next guy." Richard Feynman
    "[P]etabytes of [] data is not the same thing as understanding emergent mechanisms and structures." Jim Crutchfield

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