Physics Question - True Or False?

[Mal12345]

MC = SQR(EM)

(SQR means Square root)

 

[RaptorWizard]

Energy does indeed spring from cubes. Heck, if the box couldn't transform across contexts, relativity would be impossible!

 

[INTP]

So you are asking whether 'mass times speed of light = energy times mass times mass' is true or false?(or maybe you meant something else cuz mass is m, not M and speed of light is c, not C). If you meant that, i highly doubt that it is true, but im not an expert on physics math.

Why?

 

[93JC]

This is not a physics question; this is an algebra question, and a rather dumb one at that.

 

[Mal12345]

So you are asking whether 'mass times speed of light = energy times mass times mass' is true or false?(or maybe you meant something else cuz mass is m, not M and speed of light is c, not C). If you meant that, i highly doubt that it is true, but im not an expert on physics math.

Why?

You wrote, translated into equation form, mc=em^2. But I specified that SQR means "square root" (not "squared").

 

[Alea_iacta_est]

I have no clue as to how you manipulated that equation to look like that so I think its false
BUT
I did find this beautifully simple yet complex equation out of it.


C =

4throot(E) * 8throot(E)
-------------------------
4throot (M) * 8throot(M)

 

[Mal12345]

I have no clue as to how you manipulated that equation to look like that so I think its false
BUT
I did find this beautifully simple yet complex equation out of it.


C =

4throot(E) * 8throot(E)
-------------------------
4throot (M) * 8throot(M)

You have no clue how I did it, THEREFORE you think it's false?

 

[Alea_iacta_est]

You have no clue how I did it, THEREFORE you think it's false?

Yep. You asked whether I thought it was true or false, so I gave an answer after I looked for a possible explanation. I didn't find one from what I was doing, so the answer I have decided to provide is false. It's 50/50 isn't it?

 

[Mal12345]

Yep. You asked whether I thought it was true or false, so I gave an answer after I looked for a possible explanation. I didn't find one from what I was doing, so the answer I have decided to provide is false. It's 50/50 isn't it?

Nope, it's true, I had it vetted before coming here.

 

[Alea_iacta_est]

Nope, it's true, I had it vetted before coming here.

Damn. Well will you at least show me how you manipulated the equation?

 

[Mal12345]

Damn. Well will you at least show me how you manipulated the equation?

Start with e=mc^2, obviously.

 

[INTP]

You wrote, translated into equation form, mc=em^2. But I specified that SQR means "square root" (not "squared").

Ups, but still you didnt clarify what you are talking about. But what i wrote does not translate to what you wrote you see, M does not equal m, C does not equal c and E does not equal e. Its like linux, capital letters matter and mean completely different things.

 

[Coriolis]

MC = SQR(EM)

(SQR means Square root)

Notation aside, what is your point? This algebraic manipulation is trivial.

 

[93JC]

Notation aside, what is your point?

You think there is one?

 

[zago]

It's............................................................ genius.

 

[zago]

 

[Mal12345]

Ups, but still you didnt clarify what you are talking about. But what i wrote does not translate to what you wrote you see, M does not equal m, C does not equal c and E does not equal e. Its like linux, capital letters matter and mean completely different things.

"Ups"? I don't know what United Parcel Service has to do with it either.

But that's true, E does not equal e. I was lazy about capitalization.

 

[Coriolis]

You think there is one?

I'm giving him the benefit of the doubt (iow, enough rope for a workable noose).

 

[garbage]

I'll do obvious thing and go through the damn algebra. Why not.

• MC = SQRT(EM)
• (MC)^2 = EM (square both sides)
• M^2 * C^2 = EM (distribute square)
• M * C^2 = E (divide both sides by M)
• E = MC^2 (rearrange that stuff)

If E = e (notation for energy), M = m (notation for mass), and C = c (notation for speed of light), and if e = mc^2 is intended to represent that ol' famous general relativity equation and is assumed to be true, then the original statement is true.

(aside from stupid technical stuffs, e.g. potential division by 0 in step 4 there, which limits the domain of the equation etc. etc.)

 

[Mal12345]

Genius level = ENFJ!