Can somebody please help me with this math problem?

disregard · 02-10-2008, 08:14 PM

Step by step would be nice.

Nadir · 02-10-2008, 08:29 PM

It should be:

2*log(3) (x+6) = 2 + 2 (log (3) 9 equals 2)
2*log(3) (x+6) = 4
log(3) (x+6) = 2
x+6 = 9
x = 3

If I'm not misreading it in some way

disregard · 02-10-2008, 08:31 PM

Correct! Thanks xoxo

Nadir · 02-10-2008, 08:33 PM

Yay! You're welcome. :)

Rhadamanthus · 02-10-2008, 08:50 PM

Quote:

Originally Posted by Nadir

It should be:

2*log(3) (x+6) = 2 + 2 (log (3) 9 equals 2)
2*log(3) (x+6) = 4
log(3) (x+6) = 2
x+6 = 9
x = 3

If I'm not misreading it in some way

I don't know how people do this. I wish I was good at math.

Beat · 02-10-2008, 08:54 PM

Give me 2+2 and I can help you.

:leaves thread:

02-10-2008, 08:14 PM	#1 (permalink)
disregard Senior Member Join Date: Apr 2007 Type: Posts: 5,922	Can somebody please help me with this math problem? Step by step would be nice.

02-10-2008, 08:29 PM	#2 (permalink)
Nadir Enigma Join Date: Dec 2007 Type: INxJ Location: Istanbul, Turkey Posts: 548	It should be: 2log(3) (x+6) = 2 + 2 (log (3) 9 equals 2) 2log(3) (x+6) = 4 log(3) (x+6) = 2 x+6 = 9 x = 3 If I'm not misreading it in some way __________________ Not really.

02-10-2008, 08:33 PM	#4 (permalink)
Nadir Enigma Join Date: Dec 2007 Type: INxJ Location: Istanbul, Turkey Posts: 548	Yay! You're welcome. :) __________________ Not really.

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02-10-2008, 08:31 PM	#3 (permalink)
disregard Senior Member Join Date: Apr 2007 Type: Posts: 5,922	Correct! Thanks xoxo

02-10-2008, 08:54 PM	#6 (permalink)
Beat ...lost Join Date: Oct 2007 Type: ISTj Location: Yonder Posts: 4,808	Give me 2+2 and I can help you. :leaves thread: